Singer of the 1992 song “No Ordinary Love”

This crossword clue is for the definition: Singer of the 1992 song “No Ordinary Love”.
it’s A 42 letters crossword puzzle definition.
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Possible Answers: Sade.

Last seen on: Daily Celebrity Crossword – 7/8/18 People Sunday


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Random information on the term “Sade”:

Sade is a village in the Karmala taluka of Solapur district in Maharashtra state, India.

Covering 3,266 hectares (8,070 acres) and comprising 1077 households at the time of the 2011 census of India, Sade had a population of 4576. There were 2315 males and 2261 females, with 493 people being aged six or younger.[1]

Coordinates: 18°17′N 75°17′E / 18.283°N 75.283°E / 18.283; 75.283

Sade on Wikipedia